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Unit 3 Cheat Sheet: Sampling & Estimation

This cheat sheet provides a practical mapping framework to translate raw exam questions into correct parameters, select the appropriate formula, and compute exact confidence intervals.


1. Quick-Glance Decision Rules​

  • Proportions (pp): Always use the ZZ-distribution (SE=p^q^nSE = \sqrt{\frac{\hat{p}\hat{q}}{n}}).
  • Means (μ\mu):
    • If n≥30n \ge 30 or σ\sigma is known   ⟹  \implies ZZ-distribution (SE=σnSE = \frac{\sigma}{\sqrt{n}}).
    • If n<30n < 30 and σ\sigma is unknown   ⟹  \implies tt-distribution with df=n−1df = n - 1 (SE=snSE = \frac{s}{\sqrt{n}}).
  • Finite Population Correction (FPC): If total population NN is given and nN>0.05\frac{n}{N} > 0.05 (5%5\%)   ⟹  \implies Multiply SESE by N−nN−1\sqrt{\frac{N - n}{N - 1}}.

2. Problem-Clue Mapping Matrix​

Use this table to map keywords in exam questions directly to mathematical symbols:

Question Keyword / ClueMathematical MeaningExtracted SymbolAction Required
"Sample of 36 employees..."Sample sizen=36n = 36If n≥30n \ge 30, use ZZ-distribution.
"Sample of 15 students..."Small sample sizen=15n = 15If σ\sigma unknown, use tt-distribution (df=14df = 14).
"Population standard deviation of 6..."Known population varianceσ=6\sigma = 6Use Z=xˉ−μσ/nZ = \frac{\bar{x} - \mu}{\sigma/\sqrt{n}}.
"Sample standard deviation of 10..."Sample standard deviation onlys=10s = 10Use t=xˉ−μs/nt = \frac{\bar{x} - \mu}{s/\sqrt{n}} if n<30n < 30.
"180 reported satisfied out of 300..."Sample proportion successesx=180, n=300x = 180, \, n = 300Compute p^=180300=0.60, q^=0.40\hat{p} = \frac{180}{300} = 0.60, \, \hat{q} = 0.40.
"Assuming a total of 1000 customers..."Finite population sizeN=1000N = 1000Check nN=3001000=0.30>0.05  ⟹  \frac{n}{N} = \frac{300}{1000} = 0.30 > 0.05 \implies Apply FPC.
"At a 95% confidence level..."Confidence level (1−α1 - \alpha)1−α=0.951 - \alpha = 0.95Lookup Zα/2=1.960Z_{\alpha/2} = 1.960 or t0.025,dft_{0.025, df}.

3. The "Golden" Critical Values Table​

Memorize these two-tailed critical values for instant exam calculations:

Confidence Level (1−α1 - \alpha)Alpha (α\alpha)Tail Area (α/2\alpha/2)Normal Critical Value (ZcritZ_{\text{crit}})
90%0.100.100.050.05±1.645\pm 1.645
95%0.050.050.0250.025±1.960\pm 1.960
99%0.010.010.0050.005±2.576\pm 2.576

(Note: For tt-values, always locate the column α/2\alpha/2 matching your row df=n−1df = n - 1. Refer to the Statistical Tables Guide or view the Statistical Tables PDF.)


4. Worked Problem Archetypes​

Every Unit 3 problem maps to one of the following three templates.

Archetype 1: Population Mean with Known σ\sigma or Large Sample (ZZ-Interval)​

Exam Scenario: A random sample of 3636 employees spends an average of 22 hours22\text{ hours} on training with a population standard deviation of 6 hours6\text{ hours}. Construct a 95%95\% confidence interval for the true mean training time.

How to Map the Problem​

  1. Extract Parameters:
    • xˉ=22 hours\bar{x} = 22\text{ hours}
    • σ=6 hours\sigma = 6\text{ hours} (population standard deviation is known)
    • n=36n = 36 (n≥30  ⟹  n \ge 30 \implies Normal ZZ-distribution applies)
    • 95% confidence  ⟹  Z0.025=1.96095\%\text{ confidence} \implies Z_{0.025} = \mathbf{1.960}
  2. Calculate Standard Error (SESE): SE=σn=636=66=1.0 hourSE = \frac{\sigma}{\sqrt{n}} = \frac{6}{\sqrt{36}} = \frac{6}{6} = \mathbf{1.0\text{ hour}}
  3. Calculate Margin of Error (MEME): ME=Zα/2×SE=1.960×1.0=1.960 hoursME = Z_{\alpha/2} \times SE = 1.960 \times 1.0 = \mathbf{1.960\text{ hours}}
  4. Construct Confidence Interval: CI=xˉ±ME=22±1.960=[20.040, 23.960] hours\text{CI} = \bar{x} \pm ME = 22 \pm 1.960 = \mathbf{[20.040, \, 23.960]\text{ hours}}

Archetype 2: Population Mean with Small Sample & Unknown σ\sigma (tt-Interval)​

Exam Scenario: A researcher tests 1515 students using a new study method. The sample mean test score is 7878 with a sample standard deviation of 1010. Construct a 95%95\% confidence interval for the true average score.

How to Map the Problem​

  1. Extract Parameters:
    • xˉ=78\bar{x} = 78
    • s=10s = 10 (σ\sigma is unknown)
    • n=15n = 15 (n<30  ⟹  n < 30 \implies Small sample, requires tt-distribution)
    • Degrees of Freedom: df=n−1=15−1=14df = n - 1 = 15 - 1 = \mathbf{14}
  2. Lookup tt-Critical Value:
    • For 95%95\% confidence (α/2=0.025\alpha/2 = 0.025) with df=14df = 14: t0.025,14=2.145t_{0.025, 14} = \mathbf{2.145}
  3. Calculate Standard Error (SESE): SE=sn=1015≈103.873≈2.582SE = \frac{s}{\sqrt{n}} = \frac{10}{\sqrt{15}} \approx \frac{10}{3.873} \approx \mathbf{2.582}
  4. Calculate Margin of Error (MEME): ME=tc×SE=2.145×2.582≈5.538ME = t_c \times SE = 2.145 \times 2.582 \approx \mathbf{5.538}
  5. Construct Confidence Interval: CI=78±5.538=[72.46, 83.54]\text{CI} = 78 \pm 5.538 = \mathbf{[72.46, \, 83.54]}

Archetype 3: Proportion with Finite Population Correction (pp + FPC)​

Exam Scenario: Out of 1,0001,000 registered retail customers, a random sample of 300300 is surveyed. 180180 report being satisfied. Construct a 95%95\% confidence interval for the true proportion of satisfied customers.

How to Map the Problem​

  1. Extract Parameters:
    • N=1000N = 1000 (Total population)
    • n=300n = 300 (Sample size)
    • x=180x = 180 (Success count)
    • p^=180300=0.60,q^=1−0.60=0.40\hat{p} = \frac{180}{300} = \mathbf{0.60}, \quad \hat{q} = 1 - 0.60 = \mathbf{0.40}
    • 95% confidence  ⟹  Z0.025=1.96095\%\text{ confidence} \implies Z_{0.025} = \mathbf{1.960}
  2. Check the FPC Condition: nN=3001000=0.30 (30%)>0.05  ⟹  Must apply FPC!\frac{n}{N} = \frac{300}{1000} = 0.30\text{ (}30\%\text{)} > 0.05 \implies \text{\textbf{Must apply FPC!}}
  3. Calculate FPC Multiplier: FPC=N−nN−1=1000−3001000−1=700999≈0.837079\text{FPC} = \sqrt{\frac{N - n}{N - 1}} = \sqrt{\frac{1000 - 300}{1000 - 1}} = \sqrt{\frac{700}{999}} \approx \mathbf{0.837079}
  4. Calculate Unadjusted and Adjusted Standard Error: SE=p^q^n=0.60×0.40300=0.0008≈0.028284SE = \sqrt{\frac{\hat{p}\hat{q}}{n}} = \sqrt{\frac{0.60 \times 0.40}{300}} = \sqrt{0.0008} \approx \mathbf{0.028284} SEadj=SE×FPC=0.028284×0.837079≈0.023676SE_{\text{adj}} = SE \times \text{FPC} = 0.028284 \times 0.837079 \approx \mathbf{0.023676}
  5. Calculate Margin of Error & Interval: ME=1.960×0.023676≈0.0464ME = 1.960 \times 0.023676 \approx \mathbf{0.0464} CI=0.60±0.0464=[0.5536, 0.6464]([55.36%, 64.64%])\text{CI} = 0.60 \pm 0.0464 = \mathbf{[0.5536, \, 0.6464]}\quad (\mathbf{[55.36\%, \, 64.64\%]})

5. Universal Execution Checklist for Exams​

When solving any estimation problem, write down these 4 numbered steps on your exam script to ensure full method marks:

  1. Step 1: Identify Parameters: List n,xˉ (or p^),σ (or s),N (if given)n, \bar{x}\text{ (or } \hat{p}), \sigma\text{ (or } s), N\text{ (if given)}.
  2. Step 2: Justify Distribution Choice: State "Since n≥30n \ge 30, we use the ZZ-distribution" OR "Since n<30n < 30 and σ\sigma is unknown, we use the tt-distribution with df=n−1df = n - 1".
  3. Step 3: State & Compute SESE and MEME: Show the standard error formula and multiply by the critical value.
  4. Step 4: State Final Interval with Units: Lower Limit=Estimate−ME\text{Lower Limit} = \text{Estimate} - ME, Upper Limit=Estimate+ME\text{Upper Limit} = \text{Estimate} + ME.

6. Exam Traps & Pro-Tips​

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Common Traps to Avoid

  1. Standard Deviation vs. Standard Error: Never use σ\sigma or ss directly as your margin of error. You must always divide by n\sqrt{n} to obtain the Standard Error (SESE) before multiplying by the critical value.
  2. Forgetting FPC: If a question explicitly specifies a total population size (e.g., "Assuming a total of 1000 customers..."), it is an intentional signal to test whether you calculate and apply the FPC factor.
  3. Hypothesis Testing via Confidence Interval (Duality): When an exam question asks whether a claimed value μ0\mu_0 is supported by the sample data:
    • If μ0\mu_0 falls inside the (1−α)(1 - \alpha) interval   ⟹  \implies Fail to reject H0H_0 (Claim is plausible).
    • If μ0\mu_0 falls outside the (1−α)(1 - \alpha) interval   ⟹  \implies Reject H0H_0 (Claim is significantly different).